let a, b be Element of Benzene; :: thesis: ( a = 3 \ 2 & b = 1 implies a "\/" b = 3 )

assume A1: ( a = 3 \ 2 & b = 1 ) ; :: thesis: a "\/" b = 3

then ( a in {0,1,(3 \ 1),2,(3 \ 2),3} & b in {0,1,(3 \ 1),2,(3 \ 2),3} ) by ENUMSET1:def 4;

then reconsider aa = a, bb = b as Element of B_6 by YELLOW_1:1;

aa "\/" bb = 3 by A1, Th16;

hence a "\/" b = 3 by Th14; :: thesis: verum

assume A1: ( a = 3 \ 2 & b = 1 ) ; :: thesis: a "\/" b = 3

then ( a in {0,1,(3 \ 1),2,(3 \ 2),3} & b in {0,1,(3 \ 1),2,(3 \ 2),3} ) by ENUMSET1:def 4;

then reconsider aa = a, bb = b as Element of B_6 by YELLOW_1:1;

aa "\/" bb = 3 by A1, Th16;

hence a "\/" b = 3 by Th14; :: thesis: verum