:: A Tree of Execution of a Macroinstruction
:: by Artur Korni{\l}owicz
::
:: Received December 10, 2003
:: Copyright (c) 2003-2018 Association of Mizar Users
:: (Stowarzyszenie Uzytkownikow Mizara, Bialystok, Poland).
:: This code can be distributed under the GNU General Public Licence
:: version 3.0 or later, or the Creative Commons Attribution-ShareAlike
:: License version 3.0 or later, subject to the binding interpretation
:: detailed in file COPYING.interpretation.
:: See COPYING.GPL and COPYING.CC-BY-SA for the full text of these
:: licenses, or see http://www.gnu.org/licenses/gpl.html and
:: http://creativecommons.org/licenses/by-sa/3.0/.
environ
vocabularies NUMBERS, ORDINAL1, RELAT_1, FUNCOP_1, FUNCT_1, CARD_1, WELLORD2,
XBOOLE_0, TARSKI, SUBSET_1, ZFMISC_1, WELLORD1, ORDINAL2, FINSEQ_2,
FINSEQ_1, TREES_1, TREES_2, NAT_1, XXREAL_0, ARYTM_3, ORDINAL4, GOBOARD5,
AMI_1, AMISTD_1, GLIB_000, AMISTD_2, AMISTD_3, PARTFUN1, EXTPRO_1,
QUANTAL1, MEMSTR_0;
notations TARSKI, XBOOLE_0, ZFMISC_1, SUBSET_1, CARD_1, ORDINAL1, ORDINAL2,
NUMBERS, XXREAL_0, XCMPLX_0, NAT_1, RELAT_1, FUNCT_1, PARTFUN1, FUNCT_2,
BINOP_1, WELLORD1, WELLORD2, FUNCOP_1, FINSEQ_1, FINSEQ_2, TREES_1,
TREES_2, VALUED_1, MEASURE6, STRUCT_0, MEMSTR_0, COMPOS_1, EXTPRO_1,
AMISTD_1;
constructors WELLORD2, BINOP_1, AMISTD_2, RELSET_1, TREES_2, PRE_POLY,
AMISTD_1, FUNCOP_1, DOMAIN_1, NUMBERS, TREES_3;
registrations RELAT_1, ORDINAL1, FUNCOP_1, XXREAL_0, CARD_1, MEMBERED,
FINSEQ_1, TREES_2, FINSEQ_6, VALUED_0, FINSEQ_2, CARD_5, TREES_1,
AMISTD_2, COMPOS_1, EXTPRO_1, MEASURE6, XCMPLX_0, NAT_1;
requirements BOOLE, SUBSET, NUMERALS;
definitions RELAT_1, TARSKI, XBOOLE_0, FUNCT_1;
equalities FINSEQ_2, FUNCOP_1, AFINSQ_1, COMPOS_1, CARD_1, ORDINAL1;
expansions TARSKI, FUNCT_1;
theorems AMISTD_1, NAT_1, ORDINAL1, CARD_1, TREES_2, TREES_1, FINSEQ_1,
FUNCT_1, RELAT_1, FINSEQ_3, FINSEQ_5, TARSKI, CARD_5, FINSEQ_2, FUNCOP_1,
XXREAL_0, PARTFUN1, TREES_9, VALUED_1;
schemes TREES_2, NAT_1, HILBERT2, ORDINAL2, BINOP_1;
begin
reserve x, y, z, X for set,
m, n for Nat,
O for Ordinal,
R, S for Relation;
reserve
N for with_zero set,
S for
standard IC-Ins-separated non empty with_non-empty_values AMI-Struct over N,
L, l1 for Nat,
J for Instruction of S,
F for Subset of NAT;
:: LocSeq
definition
let N be with_zero set,
S be standard IC-Ins-separated
non empty with_non-empty_values AMI-Struct over N, M be Subset of NAT;
deffunc F(object) = canonical_isomorphism_of (RelIncl order_type_of
RelIncl M,RelIncl M).$1;
func LocSeq(M,S) -> Sequence of NAT means
:Def1:
dom it = card M & for m
being set st m in card M holds it.m = (canonical_isomorphism_of (RelIncl
order_type_of RelIncl M, RelIncl M).m);
existence
proof
consider f being Sequence such that
A1: dom f = card M and
A2: for A being Ordinal st A in card M holds f.A = F(A) from ORDINAL2:
sch 2;
f is NAT-valued
proof
let y be object;
assume y in rng f;
then consider x being object such that
A3: x in dom f & y = f.x by FUNCT_1:def 3;
reconsider x as set by TARSKI:1;
F(x) in NAT by ORDINAL1:def 12;
hence thesis by A1,A2,A3;
end;
then reconsider f as Sequence of NAT;
take f;
thus dom f = card M by A1;
let m be set;
assume m in card M;
hence thesis by A2;
end;
uniqueness
proof
let f, g be Sequence of NAT such that
A4: dom f = card M and
A5: for m being set st m in card M holds f.m = F(m) and
A6: dom g = card M and
A7: for m being set st m in card M holds g.m = F(m);
for x being object st x in dom f holds f.x = g.x
proof
let x be object such that
A8: x in dom f;
thus f.x = F(x) by A4,A5,A8
.= g.x by A4,A7,A8;
end;
hence thesis by A4,A6;
end;
end;
theorem
F = {n} implies LocSeq(F,S) = 0 .--> n
proof
assume
A1: F = {n};
then
A2: card F = {0} by CARD_1:30,49;
{n} c= omega
by ORDINAL1:def 12;
then
A3: canonical_isomorphism_of(RelIncl order_type_of RelIncl {n}, RelIncl { n}
).0 = (0 .--> n).0 by CARD_5:38
.= n by FUNCOP_1:72;
A4: dom LocSeq(F,S) = card F by Def1;
A5: for a being object st a in dom LocSeq(F,S) holds (LocSeq(F,S)).a
= (0 .--> n ) . a
proof
let a be object;
assume
A6: a in dom LocSeq(F,S);
then
A7: a = 0 by A4,A2,TARSKI:def 1;
thus (LocSeq(F,S)).a = (canonical_isomorphism_of
(RelIncl order_type_of
RelIncl F, RelIncl F).a) by A4,A6,Def1
.= (0 .--> n).a by A1,A3,A7,FUNCOP_1:72;
end;
dom (0 .--> n) = {0} by FUNCOP_1:13;
hence thesis by A1,A4,A5,CARD_1:30,49;
end;
registration
let N be with_zero set,
S be standard IC-Ins-separated
non empty with_non-empty_values AMI-Struct over N, M be Subset of NAT;
cluster LocSeq(M,S) -> one-to-one;
coherence
proof
set f = LocSeq(M,S);
set C = canonical_isomorphism_of (RelIncl order_type_of RelIncl M,RelIncl
M);
let x1,x2 be object such that
A1: x1 in dom f & x2 in dom f and
A2: f.x1 = f.x2;
A3: dom f = card M by Def1;
then
A4: f.x1 = C.x1 & f.x2 = C.x2 by A1,Def1;
A5: card M c= order_type_of RelIncl M by CARD_5:39;
consider phi being Ordinal-Sequence such that
A6: phi = C and
A7: phi is increasing and
A8: dom phi = order_type_of RelIncl M and
rng phi = M by CARD_5:5;
phi is one-to-one by A7,CARD_5:11;
hence thesis by A1,A2,A3,A4,A6,A8,A5;
end;
end;
:: Tree of Execution
definition let N be with_zero set,
S be standard IC-Ins-separated
non empty with_non-empty_values AMI-Struct over N,
M be non empty preProgram of S;
func ExecTree(M) -> DecoratedTree of NAT means
:Def2:
it.{} = FirstLoc(M) &
for t being Element of dom it holds
succ t = { t^<*k*> where k is Nat: k in card NIC(M/.(it.t),it.t) }
& for m being Nat st m in card
NIC(M/.(it.t),it.t) holds it.(t^<*m*>) = (LocSeq(NIC(M/.(it.t),it.t),S)).m;
existence
proof
defpred S[Nat,Nat] means $1 in card NIC(M/.$2,$2);
reconsider n = FirstLoc(M) as Nat;
defpred P[set,Nat,set] means ex l being Nat
st l = $1 & ($2 in dom LocSeq(NIC(M/.l,l),S) implies
$3 = (LocSeq(NIC(M/.l,l),S)).$2) &
(not $2 in dom LocSeq(NIC(M/.l,l),S) implies $3 = 0);
set D = NAT;
A1: for x, y being Element of NAT ex z being Element of NAT st P[x,y,z]
proof
let x, y be Element of NAT;
reconsider z = (LocSeq(NIC(M/.x,x),S)).y as Element of NAT
by ORDINAL1:def 12;
per cases;
suppose
A2: y in dom LocSeq(NIC(M/.x,x),S);
take z;
thus thesis by A2;
end;
suppose
A3: not y in dom LocSeq(NIC(M/.x,x),S);
reconsider il = 0 as Element of NAT;
take il;
thus thesis by A3;
end;
end;
consider f be Function of [:D,NAT:],D such that
A4: for l,n being Element of NAT holds P[l,n,f.(l,n)] from BINOP_1:sch 3(A1);
A5: for d being Element of NAT, k1, k2 being Nat st k1 <= k2 &
S[k2,d] holds S[k1,d]
proof let d be Element of NAT, k1, k2 be Nat such that
A6: k1 <= k2 and
A7: S[k2,d];
Segm k2 in card NIC(M/.d,d) by A7;
then Segm k1 in card NIC(M/.d,d) by A6,NAT_1:39,ORDINAL1:12;
hence thesis;
end;
reconsider n as Element of NAT;
consider T being DecoratedTree of NAT such that
A8: T.{} = n and
A9: for t being Element of dom T
holds succ t = { t^<*k*> where k is Nat: S[k,T.t]} &
for n being Nat st S[n,T.t] holds T.(t^
<*n*>) = f.(T.t,n) from TREES_2:sch 10(A5);
take T;
thus T.{} = FirstLoc(M) by A8;
let t be Element of dom T;
thus
succ t ={ t^<*k*> where k is Nat: S[k,T.t]} by A9;
reconsider n = T.t as Element of NAT;
let m be Nat;
A10: m in NAT by ORDINAL1:def 12;
consider l being Nat such that
A11: l = n and
A12: m in dom LocSeq(NIC(M/.l,l),S) implies
f.(n,m)= (LocSeq(NIC(M/.l,l),S)).m and
not m in dom LocSeq(NIC(M/.l,l),S) implies f.(n,m) = 0 by A4,A10;
assume m in card NIC(M/.(T.t),T.t);
hence thesis by A9,A11,A12,Def1;
end;
uniqueness
proof
let T1,T2 be DecoratedTree of NAT such that
A13: T1.{} = FirstLoc(M) and
A14: for t being Element of dom T1 holds succ t = { t^<*k*> where k is
Nat: k in card NIC(M/.(T1.t),T1.t)} & for m being Nat st
m in card NIC(M/.(T1.t),T1.t) holds T1.(t^<*m*>) =
(LocSeq(NIC(M/.(T1.t),T1.t),S)).m and
A15: T2.{} = FirstLoc(M) and
A16: for t being Element of dom T2 holds succ t = { t^<*k*> where k is
Nat: k in card NIC(M/.(T2.t),T2.t)} & for m being Nat st
m in card NIC(M/.(T2.t),T2.t) holds T2.(t^<*m*>) =
(LocSeq(NIC(M/.(T2.t),T2.t),S)).m;
defpred P[Nat] means dom T1-level $1 = dom T2-level $1;
A17: for n being Nat st P[n] holds P[n+1]
proof
let n be Nat such that
A18: P[n];
set U2 = { succ w where w is Element of dom T2 : len w = n };
set U1 = { succ w where w is Element of dom T1 : len w = n };
A19: dom T2-level n = {v where v is Element of dom T2: len v = n} by
TREES_2:def 6;
A20: dom T1-level n = {v where v is Element of dom T1: len v = n} by
TREES_2:def 6;
A21: union U1 = union U2
proof
hereby
let a be object;
assume a in union U1;
then consider A being set such that
A22: a in A and
A23: A in U1 by TARSKI:def 4;
consider w being Element of dom T1 such that
A24: A = succ w and
A25: len w = n by A23;
w in dom T1-level n by A20,A25;
then consider v being Element of dom T2 such that
A26: w = v and
A27: len v = n by A18,A19;
A28: w = w|Seg len w by FINSEQ_3:49;
defpred R[Nat] means $1 <= len w & w|Seg $1 in dom T1 & v
|Seg $1 in dom T2 implies T1.(w|Seg $1) = T2.(w|Seg $1);
A29: for n being Nat st R[n] holds R[n+1]
proof
let n be Nat;
assume that
A30: R[n] and
A31: n+1 <= len w and
A32: w|Seg (n+1) in dom T1 and
A33: v|Seg (n+1) in dom T2;
set t1 = w|Seg n;
A34: 1 <= n+1 by NAT_1:11;
A35: len(w|Seg(n+1)) = n+1 by A31,FINSEQ_1:17;
then len(w|Seg(n+1)) in Seg(n+1) by A34,FINSEQ_1:1;
then
A36: w.(n+1) = (w|Seg(n+1)).len(w|Seg(n+1)) by A35,FUNCT_1:49;
n+1 in dom w by A31,A34,FINSEQ_3:25;
then
A37: w|Seg(n+1) = t1^<*(w|Seg(n+1)).len (w|Seg(n+1))*> by A36,
FINSEQ_5:10;
A38: n <= n+1 by NAT_1:11;
then
A39: Seg n c= Seg(n+1) by FINSEQ_1:5;
then v|Seg n = v|Seg(n+1)|Seg n by RELAT_1:74;
then
A40: v|Seg n is_a_prefix_of v|Seg(n+1) by TREES_1:def 1;
w|Seg n = w|Seg(n+1)|Seg n by A39,RELAT_1:74;
then w|Seg n is_a_prefix_of w|Seg(n+1) by TREES_1:def 1;
then reconsider t1 as Element of dom T1 by A32,TREES_1:20;
reconsider t2 = t1 as Element of dom T2 by A26,A33,A40,TREES_1:20;
A41: succ t1 = { t1^<*k*> where k is Nat: k in card NIC
(M/.(T1.t1),T1.t1)} by A14;
t1^<*(w|Seg(n+1)).len(w|Seg(n+1))*> in succ t1 by A32,A37,
TREES_2:12;
then consider k being Nat such that
A42: t1^<*(w|Seg(n+1)).len(w|Seg(n+1))*> = t1^<*k*> and
A43: k in card NIC(M/.(T1.t1),T1.t1) by A41;
A44: (w|Seg(n+1)).len(w|Seg(n+1)) in card NIC(M/.(T2.t2),T2.t2)
by A30,A31,A33,A38,A40,A42,A43,FINSEQ_2:17,TREES_1:20,XXREAL_0:2;
k = (w|Seg(n+1)).len(w|Seg(n+1)) by A42,FINSEQ_2:17;
hence
T1.(w|Seg(n+1)) = (LocSeq(NIC(M/.(T1.t1),T1.t1),S)).((w|Seg(n+1
)).len (w|Seg(n+1))) by A14,A37,A43
.= T2.(w|Seg(n+1)) by A16,A30,A31,A33,A38,A40,A37,A44,
TREES_1:20,XXREAL_0:2;
end;
A45: R[0] by A13,A15;
for n being Nat holds R[n] from NAT_1:sch 2(A45,A29);
then
A46: T1.w = T2.w by A26,A28;
A47: succ v in U2 by A27;
succ v = {v^<*k*> where k is Nat:
k in card NIC(M/.(T2.v),T2.v)} &
succ w = {w^<*k*> where k is Nat:
k in card NIC(M/.(T1.w),T1.w)} by A14,A16;
hence a in union U2 by A22,A24,A26,A46,A47,TARSKI:def 4;
end;
let a be object;
assume a in union U2;
then consider A being set such that
A48: a in A and
A49: A in U2 by TARSKI:def 4;
consider w being Element of dom T2 such that
A50: A = succ w and
A51: len w = n by A49;
w in dom T2-level n by A19,A51;
then consider v being Element of dom T1 such that
A52: w = v and
A53: len v = n by A18,A20;
A54: w = w|Seg len w by FINSEQ_3:49;
defpred R[Nat] means $1 <= len w & w|Seg $1 in dom T1 & v|
Seg $1 in dom T2 implies T1.(w|Seg $1) = T2.(w|Seg $1);
A55: for n being Nat st R[n] holds R[n+1]
proof
let n be Nat;
assume that
A56: R[n] and
A57: n+1 <= len w and
A58: w|Seg (n+1) in dom T1 and
A59: v|Seg (n+1) in dom T2;
set t1 = w|Seg n;
A60: 1 <= n+1 by NAT_1:11;
A61: len(w|Seg(n+1)) = n+1 by A57,FINSEQ_1:17;
then len(w|Seg(n+1)) in Seg(n+1) by A60,FINSEQ_1:1;
then
A62: w.(n+1) = (w|Seg(n+1)).len(w|Seg(n+1)) by A61,FUNCT_1:49;
n+1 in dom w by A57,A60,FINSEQ_3:25;
then
A63: w|Seg(n+1) = t1^<*(w|Seg(n+1)).len (w|Seg(n+1))*> by A62,FINSEQ_5:10;
A64: n <= n+1 by NAT_1:11;
then
A65: Seg n c= Seg(n+1) by FINSEQ_1:5;
then v|Seg n = v|Seg(n+1)|Seg n by RELAT_1:74;
then
A66: v|Seg n is_a_prefix_of v|Seg(n+1) by TREES_1:def 1;
w|Seg n = w|Seg(n+1)|Seg n by A65,RELAT_1:74;
then w|Seg n is_a_prefix_of w|Seg(n+1) by TREES_1:def 1;
then reconsider t1 as Element of dom T1 by A58,TREES_1:20;
reconsider t2 = t1 as Element of dom T2 by A52,A59,A66,TREES_1:20;
A67: succ t1 = { t1^<*k*> where k is Nat: k in card NIC(
M/.(T1.t1),T1.t1)} by A14;
t1^<*(w|Seg(n+1)).len(w|Seg(n+1))*> in succ t1 by A58,A63,
TREES_2:12;
then consider k being Nat such that
A68: t1^<*(w|Seg(n+1)).len(w|Seg(n+1))*> = t1^<*k*> and
A69: k in card NIC(M/.(T1.t1),T1.t1) by A67;
A70: (w|Seg(n+1)).len(w|Seg(n+1)) in card NIC(M/.(T2.t2),T2.t2) by A56,A57
,A59,A64,A66,A68,A69,FINSEQ_2:17,TREES_1:20,XXREAL_0:2;
k = (w|Seg(n+1)).len(w|Seg(n+1)) by A68,FINSEQ_2:17;
hence
T1.(w|Seg(n+1)) = (LocSeq(NIC(M/.(T1.t1),T1.t1),S)).((w|Seg(n+1))
.len(w|Seg(n+1))) by A14,A63,A69
.= T2.(w|Seg(n+1)) by A16,A56,A57,A59,A64,A66,A63,A70,
TREES_1:20,XXREAL_0:2;
end;
A71: R[0] by A13,A15;
for n being Nat holds R[n] from NAT_1:sch 2(A71,A55);
then
A72: T1.w = T2.w by A52,A54;
A73: succ v in U1 by A53;
succ v = {v^<*k*> where k is Nat:
k in card NIC(M/.(T1.v),T1.v)} &
succ w = {w^<*k*> where k is Nat:
k in card NIC(M/.(T2.w),T2.w)} by A14,A16;
hence thesis by A48,A50,A52,A72,A73,TARSKI:def 4;
end;
dom T1-level (n+1) = union U1 by TREES_9:45;
hence thesis by A21,TREES_9:45;
end;
dom T1-level 0 = {{}} by TREES_9:44
.= dom T2-level 0 by TREES_9:44;
then
A74: P[0];
A75: for n being Nat holds P[n] from NAT_1:sch 2(A74,A17);
for p being FinSequence of NAT st p in dom T1 holds (T1 qua Function
).p = (T2 qua Function).p
proof
let p be FinSequence of NAT;
defpred P[Nat] means $1 <= len p & p|Seg $1 in dom T1 implies
T1.(p|Seg $1) = T2.(p|Seg $1);
A76: p|Seg len p = p by FINSEQ_3:49;
A77: for n being Nat st P[n] holds P[n+1]
proof
let n be Nat;
assume that
A78: P[n] and
A79: n+1 <= len p and
A80: p|Seg (n+1) in dom T1;
set t1 = p|Seg n;
A81: 1 <= n+1 by NAT_1:11;
A82: len(p|Seg(n+1)) = n+1 by A79,FINSEQ_1:17;
then len(p|Seg(n+1)) in Seg(n+1) by A81,FINSEQ_1:1;
then
A83: p.(n+1) = (p|Seg(n+1)).len(p|Seg(n+1)) by A82,FUNCT_1:49;
n+1 in dom p by A79,A81,FINSEQ_3:25;
then
A84: p|Seg(n+1) = t1^<*(p|Seg(n+1)).len (p|Seg(n+1))*> by A83,FINSEQ_5:10;
A85: n <= n+1 by NAT_1:11;
then Seg n c= Seg(n+1) by FINSEQ_1:5;
then p|Seg n = p|Seg(n+1)|Seg n by RELAT_1:74;
then p|Seg n is_a_prefix_of p|Seg(n+1) by TREES_1:def 1;
then reconsider t1 as Element of dom T1 by A80,TREES_1:20;
reconsider t2 = t1 as Element of dom T2 by A75,TREES_2:38;
A86: succ t1 = { t1^<*k*> where k is Nat:
k in card NIC(M/.(T1.t1),T1.t1)} by A14;
t1^<*(p|Seg(n+1)).len (p|Seg(n+1))*> in succ t1 by A80,A84,
TREES_2:12;
then consider k being Nat such that
A87: t1^<*(p|Seg(n+1)).len (p|Seg(n+1))*> = t1^<*k*> and
A88: k in card NIC(M/.(T1.t1),T1.t1) by A86;
A89: (p|Seg(n+1)).len (p|Seg(n+1)) in card NIC(M/.(T2.t2),T2.t2) by A78,A79
,A85,A87,A88,FINSEQ_2:17,XXREAL_0:2;
k = (p|Seg(n+1)).len (p|Seg(n+1)) by A87,FINSEQ_2:17;
hence
T1.(p|Seg (n+1)) = (LocSeq(NIC(M/.(T1.t1),T1.t1),S)).((p|Seg(n+1)).
len (p|Seg(n+1))) by A14,A84,A88
.= T2.(p|Seg (n+1)) by A16,A78,A79,A85,A84,A89,XXREAL_0:2;
end;
A90: P[0] by A13,A15;
for n being Nat holds P[n] from NAT_1:sch 2(A90,A77);
hence thesis by A76;
end;
hence thesis by A75,TREES_2:31,38;
end;
end;
theorem
for S being standard halting IC-Ins-separated
non empty with_non-empty_values AMI-Struct over N holds ExecTree Stop S =
TrivialInfiniteTree --> 0
proof
set D = TrivialInfiniteTree;
let S be standard halting IC-Ins-separated non empty
with_non-empty_values AMI-Struct over N;
set M = Stop S;
set E = ExecTree M;
defpred R[set] means E.$1 in dom M;
defpred X[Nat] means dom E-level $1 = D-level $1;
A1: dom M = {0} by FUNCOP_1:13;
A2: M.0 = halt S by FUNCOP_1:72;
A3: for t being Element of dom E holds card NIC(halt S,E.t) = {0}
proof
let t be Element of dom E;
reconsider Et = E.t as Nat;
NIC(halt S,Et) = {Et} by AMISTD_1:2;
hence thesis by CARD_1:30,49;
end;
A4: for f being Element of dom E st R[f]
for a being Element of NAT st f^<*a*> in dom E holds R[f^<*a*>]
proof
let f be Element of dom E such that
A5: R[f];
A6: M/.(E.f) = M.(E.f) by A5,PARTFUN1:def 6;
reconsider Ef = E.f as Nat;
A7: E.f = 0 by A1,A5,TARSKI:def 1;
then NIC(halt S,E.f) = {0} by AMISTD_1:2;
then canonical_isomorphism_of (RelIncl order_type_of RelIncl
NIC(M/.(E.f),E.f), RelIncl NIC(M/.(E.f),E.f))
= 0 .--> Ef
by A2,A7,A6,CARD_5:38;
then
A8: canonical_isomorphism_of (RelIncl order_type_of RelIncl
NIC(M/.(E.f),E.f), RelIncl NIC(M/.(E.f),E.f)).0
= Ef by FUNCOP_1:72
.= 0 by A1,A5,TARSKI:def 1;
A9: card NIC(halt S,E.f) = {0} by A3;
then
A10: 0 in card NIC(M/.(E.f),E.f) by A2,A7,A6,TARSKI:def 1;
A11: succ f = { f^<*k*> where k is Nat: k in card NIC(M/.(E.f)
,E.f) } by Def2;
A12: succ f = { f^<*0*> }
proof
hereby
let s be object;
assume s in succ f;
then consider k being Nat such that
A13: s = f^<*k*> and
A14: k in card NIC(M/.(E.f),E.f) by A11;
k = 0 by A2,A9,A7,A6,A14,TARSKI:def 1;
hence s in { f^<*0*> } by A13,TARSKI:def 1;
end;
let s be object;
assume s in { f^<*0*> };
then s = f^<*0*> by TARSKI:def 1;
hence thesis by A11,A10;
end;
let a be Element of NAT;
assume f^<*a*> in dom E;
then f^<*a*> in succ f by TREES_2:12;
then f^<*a*> = f^<*0*> by A12,TARSKI:def 1;
then E.(f^<*a*>) = (LocSeq(NIC(M/.(E.f),E.f),S)).0 by A10,Def2
.= 0 by A10,A8,Def1;
hence thesis by A1,TARSKI:def 1;
end;
E.{} = FirstLoc(M) by Def2;
then
A15: R[<*>NAT] by VALUED_1:33;
A16: for f being Element of dom E holds R[f] from HILBERT2:sch 1(A15,A4);
A17: for x being object st x in dom E holds (E qua Function).x = 0
proof
let x be object;
assume x in dom E;
then reconsider x as Element of dom E;
E.x in dom M by A16;
hence thesis by A1,TARSKI:def 1;
end;
A18: for n being Nat st X[n] holds X[n+1]
proof
let n be Nat;
set f0 = n |-> 0;
set f1 = (n+1) |-> 0;
A19: dom E-level (n+1) = {w where w is Element of dom E: len w = n+1} by
TREES_2:def 6;
A20: len f1 = n+1 by CARD_1:def 7;
assume
A21: X[n];
dom E-level (n+1) = {f1}
proof
hereby
let a be object;
assume a in dom E-level (n+1);
then consider t1 being Element of dom E such that
A22: a = t1 and
A23: len t1 = n+1 by A19;
reconsider t0 = t1|Seg n as Element of dom E by RELAT_1:59,TREES_1:20;
A24: succ t0 = { t0^<*k*> where k is Nat:
k in card NIC(M/.(E.t0),E.t0) } by Def2;
E.t0 in dom M by A16;
then
A25: E.t0 = 0 by A1,TARSKI:def 1;
A26: card NIC(halt S,E.t0) = {0} & M/.(E.t0) = M.(E.t0) by A3,A16,
PARTFUN1:def 6;
then
A27: 0 in card NIC(M/.(E.t0),E.t0) by A2,A25,TARSKI:def 1;
A28: succ t0 = { t0^<*0*> }
proof
hereby
let s be object;
assume s in succ t0;
then consider k being Nat such that
A29: s = t0^<*k*> and
A30: k in card NIC(M/.(E.t0),E.t0) by A24;
k = 0 by A2,A25,A26,A30,TARSKI:def 1;
hence s in { t0^<*0*> } by A29,TARSKI:def 1;
end;
let s be object;
assume s in { t0^<*0*> };
then s = t0^<*0*> by TARSKI:def 1;
hence thesis by A24,A27;
end;
t1.(n+1) is Nat & t1 = t0^<*t1.(n+1)*> by A23,FINSEQ_3:55;
then t0^<*t1.(n+1)*> in succ t0 by TREES_2:12;
then
A31: t0^<*t1.(n+1)*> = t0^<*0*> by A28,TARSKI:def 1;
A32: n in NAT by ORDINAL1:def 12;
n <= n+1 by NAT_1:11;
then Seg n c= Seg(n+1) by FINSEQ_1:5;
then Seg n c= dom t1 by A23,FINSEQ_1:def 3;
then dom t0 = Seg n by RELAT_1:62;
then dom E-level n = {w where w is Element of dom E: len w = n} & len
t0 = n by FINSEQ_1:def 3,TREES_2:def 6,A32;
then
A33: t0 in dom E-level n;
A34: dom E-level n = {f0} by A21,TREES_2:39;
for k being Nat st 1 <= k & k <= len t1 holds t1.k = f1.k
proof
let k be Nat;
assume 1 <= k & k <= len t1;
then
A35: k in Seg(n+1) by A23,FINSEQ_1:1;
now
per cases by A35,FINSEQ_2:7;
suppose
A36: k in Seg n;
hence t1.k = t0.k by FUNCT_1:49
.= f0.k by A34,A33,TARSKI:def 1
.= 0 by A36,FUNCOP_1:7;
end;
suppose
k = n+1;
hence t1.k = 0 by A31,FINSEQ_2:17;
end;
end;
hence thesis by A35,FUNCOP_1:7;
end;
then t1 = f1 by A20,A23,FINSEQ_1:14;
hence a in {f1} by A22,TARSKI:def 1;
end;
defpred P[Nat] means $1 |-> 0 in dom E;
let a be object;
A37: for n being Nat st P[n] holds P[n+1]
proof
let n be Nat;
assume P[n];
then reconsider t = n |-> 0 as Element of dom E;
A38: succ t = { t^<*k*> where k is Nat:
k in card NIC(M/.(E.t),E.t) } by Def2;
E.t in dom M by A16;
then
A39: E.t = 0 by A1,TARSKI:def 1;
card NIC(halt S,E.t) = {0} & M/.(E.t) = M.(E.t)
by A3,A16,PARTFUN1:def 6;
then 0 in card NIC(M/.(E.t),E.t) by A2,A39,TARSKI:def 1;
then t^<*0*> in succ t by A38;
then t^<*0*> in dom E;
hence thesis by FINSEQ_2:60;
end;
A40: P[0] by TREES_1:22;
for n being Nat holds P[n] from NAT_1:sch 2(A40,A37);
then
A41: f1 is Element of dom E;
assume a in {f1};
then a = f1 by TARSKI:def 1;
hence thesis by A19,A20,A41;
end;
hence thesis by TREES_2:39;
end;
dom E-level 0 = {{}} by TREES_9:44
.= D-level 0 by TREES_9:44;
then
A42: X[0];
for x being Nat holds X[x] from NAT_1:sch 2(A42,A18);
then dom E = D by TREES_2:38;
hence thesis by A17,FUNCOP_1:11;
end;