:: Properties of Relational Structures, Posets, Lattices and Maps
:: by Mariusz \.Zynel and Czes{\l}aw Byli\'nski
::
:: Received September 20, 1996
:: Copyright (c) 1996-2018 Association of Mizar Users
:: (Stowarzyszenie Uzytkownikow Mizara, Bialystok, Poland).
:: This code can be distributed under the GNU General Public Licence
:: version 3.0 or later, or the Creative Commons Attribution-ShareAlike
:: License version 3.0 or later, subject to the binding interpretation
:: detailed in file COPYING.interpretation.
:: See COPYING.GPL and COPYING.CC-BY-SA for the full text of these
:: licenses, or see http://www.gnu.org/licenses/gpl.html and
:: http://creativecommons.org/licenses/by-sa/3.0/.
environ
vocabularies XBOOLE_0, ORDERS_2, SUBSET_1, TARSKI, WAYBEL_0, LATTICE3,
XXREAL_0, RELAT_2, YELLOW_0, EQREL_1, LATTICES, RELAT_1, WELLORD1, CAT_1,
STRUCT_0, FUNCT_1, GROUP_6, SEQM_3, ORDINAL2, BINOP_1, REWRITE1,
SETFAM_1, CARD_FIL, YELLOW_1, ZFMISC_1, WELLORD2, YELLOW_2;
notations TARSKI, XBOOLE_0, ZFMISC_1, SUBSET_1, RELAT_1, FUNCT_1, RELSET_1,
PARTFUN1, FUNCT_2, SETFAM_1, LATTICE3, WELLORD1, DOMAIN_1, ORDERS_1,
STRUCT_0, ORDERS_2, QUANTAL1, ORDERS_3, YELLOW_0, YELLOW_1, WAYBEL_0;
constructors SETFAM_1, DOMAIN_1, TOLER_1, QUANTAL1, ORDERS_3, WAYBEL_0,
YELLOW_1, RELSET_1;
registrations XBOOLE_0, SUBSET_1, RELSET_1, FUNCT_2, STRUCT_0, LATTICE3,
YELLOW_0, WAYBEL_0, YELLOW_1;
requirements SUBSET, BOOLE;
definitions TARSKI, LATTICE3, QUANTAL1, ORDERS_3, WAYBEL_0;
equalities WAYBEL_0, STRUCT_0;
expansions TARSKI, LATTICE3, ORDERS_3, WAYBEL_0;
theorems TARSKI, RELAT_1, FUNCT_1, FUNCT_2, SETFAM_1, WELLORD1, ORDERS_2,
YELLOW_0, YELLOW_1, WAYBEL_0, XBOOLE_0, XBOOLE_1;
schemes FUNCT_2, DOMAIN_1;
begin :: Basic Facts
reserve x, X, Y for set;
theorem
for L being non empty RelStr for x being Element of L for X being
Subset of L holds X c= downarrow x iff X is_<=_than x
by WAYBEL_0:17;
theorem
for L being non empty RelStr for x being Element of L for X being
Subset of L holds X c= uparrow x iff x is_<=_than X
by WAYBEL_0:18;
theorem
for L being antisymmetric transitive with_suprema RelStr for X, Y
being set st ex_sup_of X,L & ex_sup_of Y,L holds ex_sup_of (X \/ Y),L & "\/"(X
\/ Y, L) = "\/"(X, L) "\/" "\/"(Y, L)
proof
let L be antisymmetric transitive with_suprema RelStr;
let X, Y be set such that
A1: ex_sup_of X,L and
A2: ex_sup_of Y,L;
set a = "\/"(X, L) "\/" "\/"(Y, L);
A3: X \/ Y is_<=_than a
proof
let x be Element of L;
assume
A4: x in X \/ Y;
per cases by A4,XBOOLE_0:def 3;
suppose
A5: x in X;
X is_<=_than "\/"(X, L) by A1,YELLOW_0:30;
then
A6: x <= "\/"(X, L) by A5;
"\/"(X, L) <= a by YELLOW_0:22;
hence thesis by A6,ORDERS_2:3;
end;
suppose
A7: x in Y;
Y is_<=_than "\/"(Y, L) by A2,YELLOW_0:30;
then
A8: x <= "\/"(Y, L) by A7;
"\/"(Y, L) <= a by YELLOW_0:22;
hence thesis by A8,ORDERS_2:3;
end;
end;
for b being Element of L st X \/ Y is_<=_than b holds a <= b
proof
let b be Element of L;
assume
A9: X \/ Y is_<=_than b;
Y c= X \/ Y by XBOOLE_1:7;
then Y is_<=_than b by A9;
then
A10: "\/"(Y, L) <= b by A2,YELLOW_0:30;
X c= X \/ Y by XBOOLE_1:7;
then X is_<=_than b by A9;
then "\/"(X, L) <= b by A1,YELLOW_0:30;
hence thesis by A10,YELLOW_0:22;
end;
hence thesis by A3,YELLOW_0:30;
end;
theorem
for L being antisymmetric transitive with_infima RelStr for X, Y being
set st ex_inf_of X,L & ex_inf_of Y,L holds ex_inf_of (X \/ Y),L & "/\"(X \/ Y,
L) = "/\"(X, L) "/\" "/\"(Y, L)
proof
let L be antisymmetric transitive with_infima RelStr;
let X, Y be set such that
A1: ex_inf_of X,L and
A2: ex_inf_of Y,L;
set a = "/\"(X, L) "/\" "/\"(Y, L);
A3: X \/ Y is_>=_than a
proof
let x be Element of L;
assume
A4: x in X \/ Y;
per cases by A4,XBOOLE_0:def 3;
suppose
A5: x in X;
X is_>=_than "/\"(X, L) by A1,YELLOW_0:31;
then
A6: x >= "/\"(X, L) by A5;
"/\"(X, L) >= a by YELLOW_0:23;
hence thesis by A6,ORDERS_2:3;
end;
suppose
A7: x in Y;
Y is_>=_than "/\"(Y, L) by A2,YELLOW_0:31;
then
A8: x >= "/\"(Y, L) by A7;
"/\"(Y, L) >= a by YELLOW_0:23;
hence thesis by A8,ORDERS_2:3;
end;
end;
for b being Element of L st X \/ Y is_>=_than b holds a >= b
proof
let b be Element of L;
assume
A9: X \/ Y is_>=_than b;
Y c= X \/ Y by XBOOLE_1:7;
then Y is_>=_than b by A9;
then
A10: "/\"(Y, L) >= b by A2,YELLOW_0:31;
X c= X \/ Y by XBOOLE_1:7;
then X is_>=_than b by A9;
then "/\"(X, L) >= b by A1,YELLOW_0:31;
hence thesis by A10,YELLOW_0:23;
end;
hence thesis by A3,YELLOW_0:31;
end;
begin :: Relational Substructures
theorem Th5:
for R being Relation for X, Y being set holds X c= Y implies R
|_2 X c= R |_2 Y
proof
let R be Relation, X,Y be set;
assume
A1: X c= Y;
then X|`R c= Y|`R by RELAT_1:100;
then
A2: X|`R|X c= Y|`R|X by RELAT_1:76;
Y|`R|X c= Y|`R|Y by A1,RELAT_1:75;
then X|`R|X c= Y|`R|Y by A2;
then R|_2 X c= Y|`R|Y by WELLORD1:10;
hence thesis by WELLORD1:10;
end;
theorem
for L being RelStr for S, T being full SubRelStr of L st the carrier
of S c= the carrier of T holds the InternalRel of S c= the InternalRel of T
proof
let L be RelStr, S1,S2 be full SubRelStr of L;
the InternalRel of S1 = (the InternalRel of L)|_2 the carrier of S1 &
the InternalRel of S2 = (the InternalRel of L)|_2 the carrier of S2 by
YELLOW_0:def 14;
hence thesis by Th5;
end;
theorem Th7:
for L being non empty RelStr for S being non empty SubRelStr of L
holds (X is directed Subset of S implies X is directed Subset of L) & (X is
filtered Subset of S implies X is filtered Subset of L)
proof
let L be non empty RelStr;
let S be non empty SubRelStr of L;
thus X is directed Subset of S implies X is directed Subset of L
proof
assume
A1: X is directed Subset of S;
the carrier of S c= the carrier of L by YELLOW_0:def 13;
then reconsider X as Subset of L by A1,XBOOLE_1:1;
for x, y being Element of L st x in X & y in X ex z being Element of L
st z in X & x <= z & y <= z
proof
let x, y be Element of L;
assume
A2: x in X & y in X;
then reconsider x9= x, y9= y as Element of S by A1;
consider z being Element of S such that
A3: z in X & x9 <= z & y9 <= z by A1,A2,WAYBEL_0:def 1;
reconsider z as Element of L by YELLOW_0:58;
take z;
thus thesis by A3,YELLOW_0:59;
end;
hence thesis by WAYBEL_0:def 1;
end;
thus X is filtered Subset of S implies X is filtered Subset of L
proof
assume
A4: X is filtered Subset of S;
the carrier of S c= the carrier of L by YELLOW_0:def 13;
then reconsider X as Subset of L by A4,XBOOLE_1:1;
for x, y being Element of L st x in X & y in X ex z being Element of L
st z in X & z <= x & z <= y
proof
let x, y be Element of L;
assume
A5: x in X & y in X;
then reconsider x9= x, y9= y as Element of S by A4;
consider z being Element of S such that
A6: z in X & z <= x9 & z <= y9 by A4,A5,WAYBEL_0:def 2;
reconsider z as Element of L by YELLOW_0:58;
take z;
thus thesis by A6,YELLOW_0:59;
end;
hence thesis by WAYBEL_0:def 2;
end;
end;
theorem
for L being non empty RelStr for S, T being non empty full SubRelStr
of L st the carrier of S c= the carrier of T for X being Subset of S holds X is
Subset of T & for Y being Subset of T st X = Y holds (X is filtered implies Y
is filtered) & (X is directed implies Y is directed)
proof
let L be non empty RelStr, S1,S2 be non empty full SubRelStr of L;
assume
A1: the carrier of S1 c= the carrier of S2;
let X be Subset of S1;
thus X is Subset of S2 by A1,XBOOLE_1:1;
let X2 be Subset of S2 such that
A2: X = X2;
hereby
assume
A3: X is filtered;
thus X2 is filtered
proof
let x, y be Element of S2;
assume
A4: x in X2 & y in X2;
then reconsider x9= x, y9= y as Element of S1 by A2;
consider z being Element of S1 such that
A5: z in X and
A6: z <= x9 & z <= y9 by A2,A3,A4;
reconsider x1 = x, y1 = y, z1 = z as Element of L by YELLOW_0:58;
reconsider z as Element of S2 by A2,A5;
take z;
z1 <= x1 & z1 <= y1 by A6,YELLOW_0:59;
hence thesis by A2,A5,YELLOW_0:60;
end;
end;
assume
A7: X is directed;
let x, y be Element of S2;
assume
A8: x in X2 & y in X2;
then reconsider x9= x, y9= y as Element of S1 by A2;
consider z being Element of S1 such that
A9: z in X and
A10: x9 <= z & y9 <= z by A2,A7,A8;
reconsider x1 = x, y1 = y, z1 = z as Element of L by YELLOW_0:58;
reconsider z as Element of S2 by A2,A9;
take z;
x1 <= z1 & y1 <= z1 by A10,YELLOW_0:59;
hence thesis by A2,A9,YELLOW_0:60;
end;
begin :: Maps
definition
let J be set, L be RelStr;
let f, g be Function of J, the carrier of L;
pred f <= g means
for j being set st j in J ex a, b being Element of
L st a = f.j & b = g.j & a <= b;
end;
notation
let J be set, L be RelStr;
let f, g be Function of J, the carrier of L;
synonym g >= f for f <= g;
end;
theorem
for L, M being non empty RelStr, f,g being Function of L, M holds f <=
g iff for x being Element of L holds f.x <= g.x
proof
let L, M be non empty RelStr, f,g be Function of L, M;
hereby
assume
A1: f <= g;
let x be Element of L;
ex m1,m2 being Element of M st m1 = f.x & m2 = g.x & m1 <= m2 by A1;
hence f.x <= g.x;
end;
assume
A2: for x being Element of L holds f.x <= g.x;
let x be set;
assume x in the carrier of L;
then reconsider x as Element of L;
take f.x, g.x;
thus thesis by A2;
end;
begin :: The Image of a Map
definition
let L, M be non empty RelStr;
let f be Function of L, M;
func Image f -> strict full SubRelStr of M equals
subrelstr rng f;
correctness;
end;
theorem
for L, M being non empty RelStr for f being Function of L, M for y
being Element of Image f ex x being Element of L st f.x = y
proof
let L1, L2 be non empty RelStr, g be Function of L1,L2;
let s be Element of Image g;
dom g = the carrier of L1 by FUNCT_2:def 1;
then
A1: rng g is non empty by RELAT_1:42;
rng g = the carrier of Image g by YELLOW_0:def 15;
then consider l being object such that
A2: l in dom g and
A3: s = g.l by A1,FUNCT_1:def 3;
reconsider l as Element of L1 by A2;
take l;
thus thesis by A3;
end;
registration
let L be non empty RelStr;
let X be non empty Subset of L;
cluster subrelstr X -> non empty;
coherence by YELLOW_0:def 15;
end;
registration
let L, M be non empty RelStr;
let f be Function of L, M;
cluster Image f -> non empty;
coherence
proof
dom f = the carrier of L by FUNCT_2:def 1;
then rng f is non empty by RELAT_1:42;
hence thesis;
end;
end;
begin :: Monotone Maps
theorem
for L being non empty RelStr holds id L is monotone
proof
let L be non empty RelStr;
let l1,l2 be Element of L;
assume l1 <= l2;
then l1 <= (id L).l2 by FUNCT_1:18;
hence thesis by FUNCT_1:18;
end;
theorem
for L, M, N being non empty RelStr for f being Function of L, M, g
being Function of M, N holds f is monotone & g is monotone implies g*f is
monotone
proof
let L1,L2,L3 be non empty RelStr;
let g1 be Function of L1,L2, g2 be Function of L2,L3 such that
A1: g1 is monotone and
A2: g2 is monotone;
let s1,s2 be Element of L1;
assume s1 <= s2;
then g1.s1 <= g1.s2 by A1;
then g2.(g1.s1) <= g2.(g1.s2) by A2;
then (g2*g1).s1 <= g2.(g1.s2) by FUNCT_2:15;
hence thesis by FUNCT_2:15;
end;
theorem
for L, M being non empty RelStr for f being Function of L, M for X
being Subset of L, x being Element of L holds f is monotone & x is_<=_than X
implies f.x is_<=_than f.:X
proof
let L1,L2 be non empty RelStr, g be Function of L1,L2;
let X be Subset of L1, x be Element of L1 such that
A1: g is monotone and
A2: x is_<=_than X;
let y2 be Element of L2;
assume y2 in g.:X;
then consider x2 being Element of L1 such that
A3: x2 in X and
A4: y2 = g.x2 by FUNCT_2:65;
reconsider x2 as Element of L1;
x <= x2 by A2,A3;
hence thesis by A1,A4;
end;
theorem
for L, M being non empty RelStr for f being Function of L, M for X
being Subset of L, x being Element of L holds f is monotone & X is_<=_than x
implies f.:X is_<=_than f.x
proof
let L1,L2 be non empty RelStr, g be Function of L1,L2;
let X be Subset of L1, x be Element of L1 such that
A1: g is monotone and
A2: x is_>=_than X;
let y2 be Element of L2;
assume y2 in g.:X;
then consider x2 being Element of L1 such that
A3: x2 in X and
A4: y2 = g.x2 by FUNCT_2:65;
reconsider x2 as Element of L1;
x >= x2 by A2,A3;
hence thesis by A1,A4;
end;
theorem
for S, T being non empty RelStr for f being Function of S, T for X
being directed Subset of S holds f is monotone implies f.:X is directed
proof
let S, T be non empty RelStr;
let f be Function of S, T;
let X be directed Subset of S;
set Y = f.:X;
assume
A1: f is monotone;
for y1, y2 being Element of T st y1 in Y & y2 in Y ex z being Element of
T st z in Y & y1 <= z & y2 <= z
proof
let y1, y2 be Element of T;
assume that
A2: y1 in Y and
A3: y2 in Y;
consider x1 being object such that
x1 in dom f and
A4: x1 in X and
A5: y1 = f.x1 by A2,FUNCT_1:def 6;
consider x2 being object such that
x2 in dom f and
A6: x2 in X and
A7: y2 = f.x2 by A3,FUNCT_1:def 6;
reconsider x1, x2 as Element of S by A4,A6;
consider z being Element of S such that
A8: z in X and
A9: x1 <= z & x2 <= z by A4,A6,WAYBEL_0:def 1;
take f.z;
thus f.z in Y by A8,FUNCT_2:35;
thus thesis by A1,A5,A7,A9;
end;
hence thesis;
end;
theorem Th16:
for L being with_suprema Poset for f being Function of L, L
holds f is directed-sups-preserving implies f is monotone
proof
let L be with_suprema Poset;
let f be Function of L, L;
assume
A1: f is directed-sups-preserving;
let x, y be Element of L such that
A2: x <= y;
A3: y = y"\/"x by A2,YELLOW_0:24;
for a, b being Element of L st a in {x, y} & b in {x, y} ex z being
Element of L st z in {x, y} & a <= z & b <= z
proof
let a, b be Element of L such that
A4: a in {x, y} & b in {x, y};
take y;
thus y in {x, y} by TARSKI:def 2;
thus thesis by A2,A4,TARSKI:def 2;
end;
then {x, y} is directed non empty;
then
A5: f preserves_sup_of {x, y} by A1;
A6: dom f = the carrier of L by FUNCT_2:def 1;
y <= y;
then
A7: {x, y} is_<=_than y by A2,YELLOW_0:8;
for b being Element of L st {x, y} is_<=_than b holds y <= b by YELLOW_0:8;
then ex_sup_of {x, y},L by A7,YELLOW_0:30;
then sup(f.:{x, y}) = f.sup{x, y} by A5
.= f.y by A3,YELLOW_0:41;
then
A8: f.y = sup{f.x, f.y} by A6,FUNCT_1:60
.= f.y"\/"f.x by YELLOW_0:41;
let afx, bfy be Element of L;
assume afx = f.x & bfy = f.y;
hence afx <= bfy by A8,YELLOW_0:22;
end;
theorem
for L being with_infima Poset for f being Function of L, L holds f is
filtered-infs-preserving implies f is monotone
proof
let L be with_infima Poset;
let f be Function of L, L;
assume
A1: f is filtered-infs-preserving;
let x, y be Element of L such that
A2: x <= y;
A3: x = x"/\"y by A2,YELLOW_0:25;
for c, d being Element of L st c in {x, y} & d in {x, y} ex z being
Element of L st z in {x, y} & z <= c & z <= d
proof
let c, d be Element of L such that
A4: c in {x, y} & d in {x, y};
take x;
thus x in {x, y} by TARSKI:def 2;
thus thesis by A2,A4,TARSKI:def 2;
end;
then {x, y} is filtered non empty;
then
A5: f preserves_inf_of {x, y} by A1;
A6: dom f = the carrier of L by FUNCT_2:def 1;
x <= x;
then
A7: x is_<=_than {x, y} by A2,YELLOW_0:8;
for c being Element of L st c is_<=_than {x, y} holds c <= x by YELLOW_0:8;
then ex_inf_of {x, y},L by A7,YELLOW_0:31;
then inf(f.:{x, y}) = f.inf{x, y} by A5
.= f.x by A3,YELLOW_0:40;
then
A8: f.x = inf{f.x, f.y} by A6,FUNCT_1:60
.= f.x"/\"f.y by YELLOW_0:40;
let a, b be Element of L;
assume a = f.x & b = f.y;
hence a <= b by A8,YELLOW_0:23;
end;
begin :: Idempotent Maps
theorem
for S being non empty 1-sorted for f being Function of S, S holds f is
idempotent implies for x being Element of S holds f.(f.x) = f.x
proof
let L be non empty 1-sorted, p be Function of L,L;
assume
A1: p*p = p;
let l be Element of L;
thus thesis by A1,FUNCT_2:15;
end;
theorem Th19:
for S being non empty 1-sorted for f being Function of S, S
holds f is idempotent implies rng f = {x where x is Element of S: x = f.x}
proof
let S be non empty 1-sorted;
let f be Function of S, S;
set M = {x where x is Element of S: x = f.x};
assume
A1: f = f*f;
A2: rng f c= M
proof
let y be object;
assume
A3: y in rng f;
then reconsider y9= y as Element of S;
ex x being object st x in dom f & y = f.x by A3,FUNCT_1:def 3;
then y9= f.y9 by A1,FUNCT_1:13;
hence thesis;
end;
M c= rng f
proof
let y be object;
assume y in M;
then
A4: ex y9 being Element of S st y9 = y & y9 = f.y9;
dom f = the carrier of S by FUNCT_2:def 1;
hence thesis by A4,FUNCT_1:def 3;
end;
hence thesis by A2,XBOOLE_0:def 10;
end;
theorem Th20:
for S being non empty 1-sorted for f being Function of S, S st f
is idempotent holds X c= rng f implies f.:X = X
proof
let S be non empty 1-sorted;
let f be Function of S, S such that
A1: f is idempotent;
set M = {x where x is Element of S: x = f.x};
assume X c= rng f;
then
A2: X c= M by A1,Th19;
A3: f.:X c= X
proof
let y be object;
assume y in f.:X;
then consider x being object such that
x in dom f and
A4: x in X and
A5: y = f.x by FUNCT_1:def 6;
x in M by A2,A4;
then ex x9 being Element of S st x9 = x & x9 = f.x9;
hence thesis by A4,A5;
end;
X c= f.:X
proof
let y be object;
assume
A6: y in X;
then y in M by A2;
then ex x being Element of S st x = y & x = f.x;
hence thesis by A6,FUNCT_2:35;
end;
hence thesis by A3,XBOOLE_0:def 10;
end;
theorem
for L being non empty RelStr holds id L is idempotent
proof
let L be non empty RelStr;
thus (id L)*(id L) = id ((the carrier of L) /\ (the carrier of L)) by
FUNCT_1:22
.= (id L);
end;
begin :: Complete Lattices (CCL Chapter 0, Section 2, pp. 8 -- 9)
reserve L for complete LATTICE,
a for Element of L;
theorem Th22:
a in X implies a <= "\/"(X, L) & "/\"(X, L) <= a
proof
assume
A1: a in X;
X is_<=_than "\/"(X, L) by YELLOW_0:32;
hence a <= "\/"(X, L) by A1;
X is_>=_than "/\"(X, L) by YELLOW_0:33;
hence thesis by A1;
end;
theorem Th23:
for L being non empty RelStr holds (for X holds ex_sup_of X,L)
iff (for Y holds ex_inf_of Y,L)
proof
let L be non empty RelStr;
hereby
assume
A1: for X holds ex_sup_of X,L;
let Y;
set X = {x where x is Element of L: x is_<=_than Y};
ex_sup_of X,L by A1;
then consider a being Element of L such that
A2: X is_<=_than a and
A3: for b being Element of L st X is_<=_than b holds b >= a and
A4: for c being Element of L st X is_<=_than c & for b being Element
of L st X is_<=_than b holds b >= c holds c = a by YELLOW_0:def 7;
A5: a is_<=_than Y
proof
let b be Element of L;
assume
A6: b in Y;
b is_>=_than X
proof
let c be Element of L;
assume c in X;
then ex x being Element of L st c = x & x is_<=_than Y;
hence thesis by A6;
end;
hence thesis by A3;
end;
A7: for c being Element of L st Y is_>=_than c & for b being Element of L
st Y is_>=_than b holds b <= c holds c = a
proof
let c be Element of L such that
A8: Y is_>=_than c and
A9: for b being Element of L st Y is_>=_than b holds b <= c;
A10: for b being Element of L st X is_<=_than b holds b >= c
proof
let b be Element of L;
assume
A11: X is_<=_than b;
c in X by A8;
hence thesis by A11;
end;
X is_<=_than c
proof
let b be Element of L;
assume b in X;
then ex x being Element of L st b = x & x is_<=_than Y;
hence thesis by A9;
end;
hence thesis by A4,A10;
end;
for b being Element of L st Y is_>=_than b holds a >= b
proof
let b be Element of L;
assume b is_<=_than Y;
then b in X;
hence thesis by A2;
end;
hence ex_inf_of Y,L by A5,A7,YELLOW_0:def 8;
end;
assume
A12: for Y holds ex_inf_of Y,L;
let X;
set Y = {y where y is Element of L: X is_<=_than y};
ex_inf_of Y,L by A12;
then consider a being Element of L such that
A13: Y is_>=_than a and
A14: for b being Element of L st Y is_>=_than b holds b <= a and
A15: for c being Element of L st Y is_>=_than c & for b being Element of
L st Y is_>=_than b holds b <= c holds c = a by YELLOW_0:def 8;
A16: X is_<=_than a
proof
let b be Element of L;
assume
A17: b in X;
b is_<=_than Y
proof
let c be Element of L;
assume c in Y;
then ex y being Element of L st c = y & X is_<=_than y;
hence thesis by A17;
end;
hence thesis by A14;
end;
A18: for c being Element of L st X is_<=_than c & for b being Element of L
st X is_<=_than b holds b >= c holds c = a
proof
let c be Element of L such that
A19: X is_<=_than c and
A20: for b being Element of L st X is_<=_than b holds b >= c;
A21: for b being Element of L st Y is_>=_than b holds b <= c
proof
let b be Element of L;
assume
A22: Y is_>=_than b;
c in Y by A19;
hence thesis by A22;
end;
Y is_>=_than c
proof
let b be Element of L;
assume b in Y;
then ex x being Element of L st b = x & x is_>=_than X;
hence thesis by A20;
end;
hence thesis by A15,A21;
end;
for b being Element of L st X is_<=_than b holds a <= b
proof
let b be Element of L;
assume X is_<=_than b;
then b in Y;
hence thesis by A13;
end;
hence thesis by A16,A18,YELLOW_0:def 7;
end;
theorem Th24: ::Proposition 2.2 (i) (variant 1) cf YELLOW_0
for L being non empty RelStr holds (for X holds ex_sup_of X,L)
implies L is complete
proof
let L be non empty RelStr;
assume
A1: for X holds ex_sup_of X,L;
L is complete
proof
let X be set;
take a = "\/"(X, L);
A2: ex_sup_of X,L by A1;
hence X is_<=_than a by YELLOW_0:def 9;
thus thesis by A2,YELLOW_0:def 9;
end;
hence thesis;
end;
theorem Th25: ::Proposition 2.2 (i) (variant 2) cf variant 3
for L being non empty RelStr holds (for X holds ex_inf_of X,L)
implies L is complete
proof
let L be non empty RelStr;
assume for X holds ex_inf_of X,L;
then for X holds ex_sup_of X,L by Th23;
hence thesis by Th24;
end;
theorem Th26:
for L being non empty RelStr holds (for A being Subset of L
holds ex_inf_of A, L) implies for X holds ex_inf_of X,L & "/\"(X, L) = "/\"(X
/\ the carrier of L, L)
proof
let L be non empty RelStr;
assume
A1: for A being Subset of L holds ex_inf_of A, L;
let X;
set Y = X /\ the carrier of L;
set a = "/\"(Y, L);
reconsider Y as Subset of L by XBOOLE_1:17;
A2: ex_inf_of Y,L by A1;
A3: a is_<=_than X
proof
let x be Element of L;
assume x in X;
then
A4: x in Y by XBOOLE_0:def 4;
a is_<=_than Y by A2,YELLOW_0:def 10;
hence thesis by A4;
end;
A5: for b being Element of L st b is_<=_than X holds b <= a
proof
let b be Element of L;
A6: Y c= X by XBOOLE_1:17;
assume b is_<=_than X;
then b is_<=_than Y by A6;
hence thesis by A2,YELLOW_0:def 10;
end;
ex_inf_of X,L by A2,YELLOW_0:50;
hence thesis by A3,A5,YELLOW_0:def 10;
end;
theorem
for L being non empty RelStr holds (for A being Subset of L holds
ex_sup_of A, L) implies for X holds ex_sup_of X,L & "\/"(X, L) = "\/"(X /\ the
carrier of L, L)
proof
let L be non empty RelStr;
assume
A1: for A being Subset of L holds ex_sup_of A, L;
let X;
set Y = X /\ the carrier of L;
set a = "\/"(Y, L);
reconsider Y as Subset of L by XBOOLE_1:17;
A2: ex_sup_of Y,L by A1;
A3: X is_<=_than a
proof
let x be Element of L;
assume x in X;
then
A4: x in Y by XBOOLE_0:def 4;
Y is_<=_than a by A2,YELLOW_0:def 9;
hence thesis by A4;
end;
A5: for b being Element of L st X is_<=_than b holds a <= b
proof
let b be Element of L;
A6: Y c= X by XBOOLE_1:17;
assume X is_<=_than b;
then Y is_<=_than b by A6;
hence thesis by A2,YELLOW_0:def 9;
end;
ex_sup_of X,L by A2,YELLOW_0:50;
hence thesis by A3,A5,YELLOW_0:def 9;
end;
theorem Th28: ::Proposition 2.2 (i) (variant 3)
for L being non empty RelStr holds (for A being Subset of L
holds ex_inf_of A,L) implies L is complete
proof
let L be non empty RelStr;
assume for A being Subset of L holds ex_inf_of A,L;
then for X holds ex_inf_of X, L by Th26;
hence thesis by Th25;
end;
registration
cluster up-complete /\-complete upper-bounded -> complete for
non empty Poset;
correctness;
end;
theorem Th29: :: Theorem 2.3 (The Fixed-Point Theorem)
for f being Function of L, L st f is monotone for M being Subset
of L st M = {x where x is Element of L: x = f.x} holds subrelstr M is complete
LATTICE
proof
let f be Function of L, L such that
A1: f is monotone;
let M be Subset of L such that
A2: M = {x where x is Element of L: x = f.x};
set S = subrelstr M;
A3: for X being Subset of S for Y being Subset of L st Y = {y where y is
Element of L: X is_<=_than f.y & f.y <= y} holds inf Y in M
proof
let X be Subset of S;
let Y be Subset of L such that
A4: Y = {y where y is Element of L: X is_<=_than f.y & f.y <= y};
set z = inf Y;
A5: f.z is_<=_than Y
proof
let u be Element of L;
assume
A6: u in Y;
then consider y being Element of L such that
A7: y = u and
X is_<=_than f.y and
A8: f.y <= y by A4;
z <= u by A6,Th22;
then f.z <= f.y by A1,A7;
hence f.z <= u by A7,A8,ORDERS_2:3;
end;
A9: X is_<=_than f.(f.z)
proof
let m be Element of L;
assume
A10: m in X;
m is_<=_than Y
proof
let u be Element of L;
assume u in Y;
then consider y being Element of L such that
A11: y = u and
A12: X is_<=_than f.y and
A13: f.y <= y by A4;
m <= f.y by A10,A12;
hence m <= u by A11,A13,ORDERS_2:3;
end;
then m <= z by YELLOW_0:33;
then
A14: f.m <= f.z by A1;
X c= the carrier of S;
then X c= M by YELLOW_0:def 15;
then m in M by A10;
then ex x being Element of L st x = m & x = f.x by A2;
hence m <= f.(f.z) by A1,A14;
end;
ex_inf_of Y,L by YELLOW_0:17;
then
A15: f.z <= z by A5,YELLOW_0:31;
then f.(f.z) <= f.z by A1;
then f.z in Y by A4,A9;
then z <= f.z by Th22;
then z = f.z by A15,ORDERS_2:2;
hence thesis by A2;
end;
M c= the carrier of S by YELLOW_0:def 15;
then reconsider M as Subset of S;
defpred P[Element of L] means M is_<=_than f.$1 & f.$1 <= $1;
reconsider Y = {y where y is Element of L: P[y]} as Subset of L from
DOMAIN_1:sch 7;
inf Y in M by A3;
then reconsider S as non empty Poset;
for X being Subset of S holds ex_sup_of X, S
proof
let X be Subset of S;
defpred Q[Element of L] means X is_<=_than f.$1 & f.$1 <= $1;
reconsider Y = {y where y is Element of L: Q[y]} as Subset of L from
DOMAIN_1:sch 7;
set z = inf Y;
z in M by A3;
then reconsider z as Element of S;
A16: X is_<=_than z
proof
let x be Element of S;
x in the carrier of S;
then x in M by YELLOW_0:def 15;
then consider m being Element of L such that
A17: x = m and
m = f.m by A2;
assume
A18: x in X;
m is_<=_than Y
proof
let u be Element of L;
assume u in Y;
then consider y being Element of L such that
A19: y = u and
A20: X is_<=_than f.y and
A21: f.y <= y;
m <= f.y by A18,A17,A20;
hence m <= u by A19,A21,ORDERS_2:3;
end;
then m <= inf Y by YELLOW_0:33;
hence x <= z by A17,YELLOW_0:60;
end;
for b being Element of S st X is_<=_than b holds z <= b
proof
let b be Element of S;
b in the carrier of S;
then b in M by YELLOW_0:def 15;
then consider x being Element of L such that
A22: x = b and
A23: x = f.x by A2;
assume X is_<=_than b;
then X is_<=_than f.x by A22,A23,YELLOW_0:62;
then x in Y by A23;
hence thesis by A22,Th22,YELLOW_0:60;
end;
hence thesis by A16,YELLOW_0:30;
end;
then reconsider S as complete non empty Poset by YELLOW_0:53;
S is complete LATTICE;
hence thesis;
end;
theorem Th30:
for S being infs-inheriting non empty full SubRelStr of L holds
S is complete LATTICE
proof
let S be infs-inheriting non empty full SubRelStr of L;
for X being Subset of S holds ex_inf_of X,S
proof
let X be Subset of S;
A1: ex_inf_of X,L by YELLOW_0:17;
then "/\"(X,L) in the carrier of S by YELLOW_0:def 18;
hence thesis by A1,YELLOW_0:63;
end;
then S is complete by Th28;
hence thesis;
end;
theorem Th31:
for S being sups-inheriting non empty full SubRelStr of L holds
S is complete LATTICE
proof
let S be sups-inheriting non empty full SubRelStr of L;
for X being Subset of S holds ex_sup_of X, S
proof
let X be Subset of S;
A1: ex_sup_of X,L by YELLOW_0:17;
then "\/"(X,L) in the carrier of S by YELLOW_0:def 19;
hence thesis by A1,YELLOW_0:64;
end;
then S is complete by YELLOW_0:53;
hence thesis;
end;
theorem Th32: ::Remark 2.4 (Part I, variant 1)
for M being non empty RelStr for f being Function of L, M st f
is sups-preserving holds Image f is sups-inheriting
proof
let M be non empty RelStr;
let f be Function of L, M such that
A1: f is sups-preserving;
set S = subrelstr(rng f);
for Y being Subset of S st ex_sup_of Y,M holds "\/"(Y, M) in the carrier of S
proof
let Y be Subset of S;
assume ex_sup_of Y,M;
A2: f preserves_sup_of (f"Y) & ex_sup_of f"Y,L by A1,YELLOW_0:17;
Y c= the carrier of S;
then Y c= rng f by YELLOW_0:def 15;
then "\/"(Y, M) = sup(f.:(f"Y)) by FUNCT_1:77
.= f.sup(f"Y) by A2;
then "\/"(Y, M) in rng f by FUNCT_2:4;
hence thesis by YELLOW_0:def 15;
end;
hence thesis by YELLOW_0:def 19;
end;
theorem Th33: ::Remark 2.4 (Part I, variant 2)
for M being non empty RelStr for f being Function of L, M st f
is infs-preserving holds Image f is infs-inheriting
proof
let M be non empty RelStr;
let f be Function of L, M such that
A1: f is infs-preserving;
set S = subrelstr(rng f);
for Y being Subset of S st ex_inf_of Y,M holds "/\"(Y, M) in the carrier of S
proof
let Y be Subset of S;
assume ex_inf_of Y,M;
A2: f preserves_inf_of (f"Y) & ex_inf_of f"Y,L by A1,YELLOW_0:17;
Y c= the carrier of S;
then Y c= rng f by YELLOW_0:def 15;
then "/\"(Y, M) = inf(f.:(f"Y)) by FUNCT_1:77
.= f.inf(f"Y) by A2;
then "/\"(Y, M) in rng f by FUNCT_2:4;
hence thesis by YELLOW_0:def 15;
end;
hence thesis by YELLOW_0:def 18;
end;
theorem ::Remark 2.4 (Part II)
for L, M being complete LATTICE for f being Function of L, M st f is
sups-preserving or f is infs-preserving holds Image f is complete LATTICE
proof
let L, M be complete LATTICE;
let f be Function of L, M such that
A1: f is sups-preserving or f is infs-preserving;
per cases by A1;
suppose
f is sups-preserving;
then Image f is sups-inheriting by Th32;
hence thesis by Th31;
end;
suppose
f is infs-preserving;
then Image f is infs-inheriting by Th33;
hence thesis by Th30;
end;
end;
theorem ::Remark 2.5
for f being Function of L, L st f is idempotent
directed-sups-preserving holds Image f is directed-sups-inheriting & Image f is
complete LATTICE
proof
let f be Function of L, L;
set S = subrelstr(rng f);
set a = the Element of L;
dom f = the carrier of L by FUNCT_2:def 1;
then f.a in rng f by FUNCT_1:def 3;
then reconsider S9= S as non empty full SubRelStr of L;
assume
A1: f is idempotent directed-sups-preserving;
for X being directed Subset of S st X <> {} & ex_sup_of X,L holds "\/"(X
,L) in the carrier of S
proof
let X be directed Subset of S;
X c= the carrier of S;
then
A2: X c= rng f by YELLOW_0:def 15;
assume X <> {};
then X is non empty directed Subset of S9;
then reconsider X9= X as non empty directed Subset of L by Th7;
assume
A3: ex_sup_of X,L;
f preserves_sup_of X9 by A1;
then sup(f.:X9) = f.sup X9 by A3;
then sup X9 = f.sup X9 by A1,A2,Th20;
then "\/"(X, L) in rng f by FUNCT_2:4;
hence thesis by YELLOW_0:def 15;
end;
hence Image f is directed-sups-inheriting;
rng f = {x where x is Element of L: x = f.x} by A1,Th19;
hence thesis by A1,Th16,Th29;
end;
begin :: A Lattice of Ideals
theorem Th36:
for L being RelStr for F being Subset-Family of L st for X being
Subset of L st X in F holds X is lower holds meet F is lower Subset of L
proof
let L be RelStr;
let F be Subset-Family of L;
reconsider F9 = F as Subset-Family of L;
assume
A1: for X being Subset of L st X in F holds X is lower;
reconsider M = meet F9 as Subset of L;
per cases;
suppose
F = {};
then for x, y being Element of L st x in M & y <= x holds y in M by
SETFAM_1:def 1;
hence thesis by WAYBEL_0:def 19;
end;
suppose
A2: F <> {};
for x, y being Element of L st x in M & y <= x holds y in M
proof
let x, y be Element of L;
assume that
A3: x in M and
A4: y <= x;
for Y being set st Y in F holds y in Y
proof
let Y be set;
assume
A5: Y in F;
then reconsider X = Y as Subset of L;
X is lower & x in X by A1,A3,A5,SETFAM_1:def 1;
hence thesis by A4;
end;
hence thesis by A2,SETFAM_1:def 1;
end;
hence thesis by WAYBEL_0:def 19;
end;
end;
theorem
for L being RelStr for F being Subset-Family of L st for X being
Subset of L st X in F holds X is upper holds meet F is upper Subset of L
proof
let L be RelStr;
let F be Subset-Family of L;
reconsider F9 = F as Subset-Family of L;
assume
A1: for X being Subset of L st X in F holds X is upper;
reconsider M = meet F9 as Subset of L;
per cases;
suppose
F = {};
then for x, y being Element of L st x in M & x <= y holds y in M by
SETFAM_1:def 1;
hence thesis by WAYBEL_0:def 20;
end;
suppose
A2: F <> {};
for x, y being Element of L st x in M & x <= y holds y in M
proof
let x, y be Element of L;
assume that
A3: x in M and
A4: x <= y;
for Y being set st Y in F holds y in Y
proof
let Y be set;
assume
A5: Y in F;
then reconsider X = Y as Subset of L;
X is upper & x in X by A1,A3,A5,SETFAM_1:def 1;
hence thesis by A4;
end;
hence thesis by A2,SETFAM_1:def 1;
end;
hence thesis by WAYBEL_0:def 20;
end;
end;
theorem Th38:
for L being with_suprema antisymmetric RelStr for F being
Subset-Family of L st for X being Subset of L st X in F holds X is lower
directed holds meet F is directed Subset of L
proof
let L be with_suprema antisymmetric RelStr;
let F be Subset-Family of L;
assume
A1: for X being Subset of L st X in F holds X is lower directed;
reconsider F9 = F as Subset-Family of L;
reconsider M = meet F9 as Subset of L;
per cases;
suppose
A2: F = {};
M is directed
by A2,SETFAM_1:def 1;
hence thesis;
end;
suppose
A3: F <> {};
M is directed
proof
let x, y be Element of L such that
A4: x in M and
A5: y in M;
take z = x"\/"y;
for Y being set st Y in F holds z in Y
proof
let Y be set;
assume
A6: Y in F;
then reconsider X = Y as Subset of L;
A7: y in X by A5,A6,SETFAM_1:def 1;
X is lower directed & x in X by A1,A4,A6,SETFAM_1:def 1;
hence thesis by A7,WAYBEL_0:40;
end;
hence z in M by A3,SETFAM_1:def 1;
thus thesis by YELLOW_0:22;
end;
hence thesis;
end;
end;
theorem
for L being with_infima antisymmetric RelStr for F being Subset-Family
of L st for X being Subset of L st X in F holds X is upper filtered holds meet
F is filtered Subset of L
proof
let L be with_infima antisymmetric RelStr;
let F be Subset-Family of L;
assume
A1: for X being Subset of L st X in F holds X is upper filtered;
reconsider F9 = F as Subset-Family of L;
reconsider M = meet F9 as Subset of L;
per cases;
suppose
A2: F = {};
M is filtered
by A2,SETFAM_1:def 1;
hence thesis;
end;
suppose
A3: F <> {};
M is filtered
proof
let x, y be Element of L such that
A4: x in M and
A5: y in M;
take z = x"/\"y;
for Y being set st Y in F holds z in Y
proof
let Y be set;
assume
A6: Y in F;
then reconsider X = Y as Subset of L;
A7: y in X by A5,A6,SETFAM_1:def 1;
X is upper filtered & x in X by A1,A4,A6,SETFAM_1:def 1;
hence thesis by A7,WAYBEL_0:41;
end;
hence z in M by A3,SETFAM_1:def 1;
thus thesis by YELLOW_0:23;
end;
hence thesis;
end;
end;
theorem Th40:
for L being with_infima Poset for I, J being Ideal of L holds I
/\ J is Ideal of L
proof
let L be with_infima Poset;
let I, J be Ideal of L;
set i = the Element of I,j = the Element of J;
set a = i"/\"j;
a <= j by YELLOW_0:23;
then
A1: a in J by WAYBEL_0:def 19;
a <= i by YELLOW_0:23;
then a in I by WAYBEL_0:def 19;
hence thesis by A1,WAYBEL_0:27,44,XBOOLE_0:def 4;
end;
registration
let L be non empty reflexive transitive RelStr;
cluster Ids L -> non empty;
correctness
proof
set x = the Element of L;
downarrow x in the set of all Y where Y is Ideal of L;
hence thesis;
end;
end;
theorem Th41:
for L being non empty reflexive transitive RelStr holds (x is
Element of InclPoset(Ids L) iff x is Ideal of L)
proof
let L be non empty reflexive transitive RelStr;
hereby
assume x is Element of InclPoset(Ids L);
then x in the carrier of InclPoset(Ids L);
then x in Ids L by YELLOW_1:1;
then ex J being Ideal of L st J = x;
hence x is Ideal of L;
end;
assume x is Ideal of L;
then x in the set of all Y where Y is Ideal of L;
hence thesis by YELLOW_1:1;
end;
theorem Th42:
for L being non empty reflexive transitive RelStr for I being
Element of InclPoset(Ids L) holds x in I implies x is Element of L
proof
let L be non empty reflexive transitive RelStr;
let I be Element of InclPoset(Ids L);
reconsider I9= I as non empty Subset of L by Th41;
assume x in I;
then reconsider x9= x as Element of I9;
x9 in the carrier of L;
hence thesis;
end;
theorem
for L being with_infima Poset for x, y being Element of InclPoset(Ids
L) holds x "/\" y = x /\ y
proof
let L be with_infima Poset;
let x, y be Element of InclPoset(Ids L);
reconsider x9= x, y9= y as Ideal of L by Th41;
x9 /\ y9 is Ideal of L by Th40;
then x9 /\ y9 in the set of all X where X is Ideal of L;
hence thesis by YELLOW_1:9;
end;
registration
let L be with_infima Poset;
cluster InclPoset(Ids L) -> with_infima;
correctness
proof
for x, y be set st x in Ids L & y in Ids L holds x /\ y in Ids L
proof
let x, y be set;
assume that
A1: x in Ids L and
A2: y in Ids L;
consider I being Ideal of L such that
A3: I = x by A1;
consider J being Ideal of L such that
A4: J = y by A2;
I /\ J is Ideal of L by Th40;
hence thesis by A3,A4;
end;
hence thesis by YELLOW_1:12;
end;
end;
theorem Th44:
for L being with_suprema Poset for x, y being Element of
InclPoset(Ids L) holds ex Z being Subset of L st Z = {z where z is Element of L
: z in x or z in y or ex a, b being Element of L st a in x & b in y & z = a
"\/" b} & ex_sup_of {x, y},InclPoset(Ids L) & x "\/" y = downarrow Z
proof
let L be with_suprema Poset;
set P = InclPoset(Ids L);
let x, y be Element of P;
defpred P[Element of L] means $1 in x or $1 in y or ex a, b being Element of
L st a in x & b in y & $1 = a "\/" b;
reconsider Z = {z where z is Element of L: P[z]} as Subset of L from
DOMAIN_1:sch 7;
take Z;
reconsider x9= x, y9= y as Ideal of L by Th41;
set z = the Element of x9;
z in Z;
then reconsider Z as non empty Subset of L;
set DZ = downarrow Z;
for u, v being Element of L st u in Z & v in Z ex z being Element of L
st z in Z & u <= z & v <= z
proof
A1: for p, q being Element of L st p in y & ex a, b being Element of L st
a in x & b in y & q = a "\/" b holds ex z being Element of L st z in Z & p <= z
& q <= z
proof
let p, q be Element of L such that
A2: p in y and
A3: ex a, b being Element of L st a in x & b in y & q = a "\/" b;
consider a, b being Element of L such that
A4: a in x and
A5: b in y and
A6: q = a "\/" b by A3;
reconsider c = b "\/" p as Element of L;
take z = a "\/" c;
c in y9 by A2,A5,WAYBEL_0:40;
hence z in Z by A4;
A7: c <= z by YELLOW_0:22;
A8: p <= c & a <= z by YELLOW_0:22;
b <= c by YELLOW_0:22;
then b <= z by A7,ORDERS_2:3;
hence thesis by A6,A7,A8,ORDERS_2:3,YELLOW_0:22;
end;
A9: for p, q being Element of L st p in x & ex a, b being Element of L st
a in x & b in y & q = a "\/" b holds ex z being Element of L st z in Z & p <= z
& q <= z
proof
let p, q be Element of L such that
A10: p in x and
A11: ex a, b being Element of L st a in x & b in y & q = a "\/" b;
consider a, b being Element of L such that
A12: a in x and
A13: b in y and
A14: q = a "\/" b by A11;
reconsider c = a "\/" p as Element of L;
take z = c "\/" b;
c in x9 by A10,A12,WAYBEL_0:40;
hence z in Z by A13;
A15: c <= z by YELLOW_0:22;
A16: p <= c & b <= z by YELLOW_0:22;
a <= c by YELLOW_0:22;
then a <= z by A15,ORDERS_2:3;
hence thesis by A14,A15,A16,ORDERS_2:3,YELLOW_0:22;
end;
let u, v be Element of L such that
A17: u in Z and
A18: v in Z;
consider p being Element of L such that
A19: p = u and
A20: p in x or p in y or ex a, b being Element of L st a in x & b in y
& p = a "\/" b by A17;
consider q being Element of L such that
A21: q = v and
A22: q in x or q in y or ex a, b being Element of L st a in x & b in y
& q = a "\/" b by A18;
per cases by A20,A22;
suppose
p in x & q in x;
then consider z being Element of L such that
A23: z in x9 & p <= z & q <= z by WAYBEL_0:def 1;
take z;
thus thesis by A19,A21,A23;
end;
suppose
A24: p in x & q in y;
take p "\/" q;
thus thesis by A19,A21,A24,YELLOW_0:22;
end;
suppose
p in x & ex a, b being Element of L st a in x & b in y & q = a "\/" b;
then consider z being Element of L such that
A25: z in Z & p <= z & q <= z by A9;
take z;
thus thesis by A19,A21,A25;
end;
suppose
A26: p in y & q in x;
take q "\/" p;
thus thesis by A19,A21,A26,YELLOW_0:22;
end;
suppose
p in y & q in y;
then consider z being Element of L such that
A27: z in y9 & p <= z & q <= z by WAYBEL_0:def 1;
take z;
thus thesis by A19,A21,A27;
end;
suppose
p in y & ex a, b being Element of L st a in x & b in y & q = a "\/" b;
then consider z being Element of L such that
A28: z in Z & p <= z & q <= z by A1;
take z;
thus thesis by A19,A21,A28;
end;
suppose
q in x & ex a, b being Element of L st a in x & b in y & p = a "\/" b;
then consider z being Element of L such that
A29: z in Z & q <= z & p <= z by A9;
take z;
thus thesis by A19,A21,A29;
end;
suppose
q in y & ex a, b being Element of L st a in x & b in y & p = a "\/" b;
then consider z being Element of L such that
A30: z in Z & q <= z & p <= z by A1;
take z;
thus thesis by A19,A21,A30;
end;
suppose
(ex a, b being Element of L st a in x & b in y & p = a "\/" b)
& ex a, b being Element of L st a in x & b in y & q = a "\/" b;
then consider a, b, c, d being Element of L such that
A31: a in x & b in y and
A32: p = a "\/" b and
A33: c in x & d in y and
A34: q = c "\/" d;
reconsider ac = a "\/" c, bd = b "\/" d as Element of L;
take z = ac "\/" bd;
ac in x9 & bd in y9 by A31,A33,WAYBEL_0:40;
hence z in Z;
A35: ac <= z by YELLOW_0:22;
A36: bd <= z by YELLOW_0:22;
b <= bd by YELLOW_0:22;
then
A37: b <= z by A36,ORDERS_2:3;
a <= ac by YELLOW_0:22;
then a <= z by A35,ORDERS_2:3;
hence u <= z by A19,A32,A37,YELLOW_0:22;
d <= bd by YELLOW_0:22;
then
A38: d <= z by A36,ORDERS_2:3;
c <= ac by YELLOW_0:22;
then c <= z by A35,ORDERS_2:3;
hence thesis by A21,A34,A38,YELLOW_0:22;
end;
end;
then Z is directed;
then reconsider DZ as Element of P by Th41;
A39: for d being Element of P st d >= x & d >= y holds DZ <= d
proof
let d be Element of P;
assume that
A40: x <= d and
A41: y <= d;
A42: y c= d by A41,YELLOW_1:3;
A43: x c= d by A40,YELLOW_1:3;
DZ c= d
proof
let p be object;
assume p in DZ;
then p in {q where q is Element of L: ex u being Element of L st q <= u
& u in Z} by WAYBEL_0:14;
then consider p9 being Element of L such that
A44: p9 = p and
A45: ex u being Element of L st p9 <= u & u in Z;
consider u being Element of L such that
A46: p9 <= u and
A47: u in Z by A45;
consider z being Element of L such that
A48: z = u and
A49: z in x or z in y or ex a, b being Element of L st a in x & b in
y & z = a "\/" b by A47;
per cases by A49;
suppose
z in x;
then p in x9 by A44,A46,A48,WAYBEL_0:def 19;
hence thesis by A43;
end;
suppose
z in y;
then p in y9 by A44,A46,A48,WAYBEL_0:def 19;
hence thesis by A42;
end;
suppose
A50: ex a, b being Element of L st a in x & b in y & z = a "\/" b;
reconsider d9= d as Ideal of L by Th41;
u in d9 by A43,A42,A48,A50,WAYBEL_0:40;
hence thesis by A44,A46,WAYBEL_0:def 19;
end;
end;
hence thesis by YELLOW_1:3;
end;
y c= DZ
proof
let a be object;
A51: Z c= DZ by WAYBEL_0:16;
assume
A52: a in y;
then reconsider a9= a as Element of L by Th42;
a9 in Z by A52;
hence thesis by A51;
end;
then
A53: y <= DZ by YELLOW_1:3;
x c= DZ
proof
let a be object;
A54: Z c= DZ by WAYBEL_0:16;
assume
A55: a in x;
then reconsider a9= a as Element of L by Th42;
a9 in Z by A55;
hence thesis by A54;
end;
then x <= DZ by YELLOW_1:3;
hence thesis by A53,A39,YELLOW_0:18;
end;
registration
let L be with_suprema Poset;
cluster InclPoset(Ids L) -> with_suprema;
correctness
proof
set P = InclPoset(Ids L);
for x, y being Element of P ex z being Element of P st x <= z & y <= z
& for z9 being Element of P st x <= z9 & y <= z9 holds z <= z9
proof
let x, y be Element of P;
take x "\/" y;
ex Z being Subset of L st Z = {z where z is Element of L: z in x or z
in y or ex a, b being Element of L st a in x & b in y & z = a "\/" b} &
ex_sup_of {x, y},InclPoset(Ids L) & x "\/" y = downarrow Z by Th44;
hence thesis by YELLOW_0:18;
end;
hence thesis;
end;
end;
theorem Th45:
for L being lower-bounded sup-Semilattice for X being non empty
Subset of Ids L holds meet X is Ideal of L
proof
let L be lower-bounded sup-Semilattice;
let X be non empty Subset of Ids L;
A1: for J being set st J in X holds J is Ideal of L
proof
let J be set;
assume J in X;
then J in Ids L;
then ex Y being Ideal of L st Y = J;
hence thesis;
end;
X c= bool the carrier of L
proof
let x be object;
assume x in X;
then x is Ideal of L by A1;
hence thesis;
end;
then reconsider F = X as Subset-Family of L;
for J being Subset of L st J in F holds J is lower by A1;
then reconsider I = meet X as lower Subset of L by Th36;
for J being set st J in X holds Bottom L in J
proof
let J be set;
assume J in X;
then reconsider J9= J as Ideal of L by A1;
set j = the Element of J9;
Bottom L <= j by YELLOW_0:44;
hence thesis by WAYBEL_0:def 19;
end;
then reconsider I as non empty lower Subset of L by SETFAM_1:def 1;
for J being Subset of L st J in F holds J is lower directed by A1;
then I is Ideal of L by Th38;
hence thesis;
end;
theorem Th46:
for L being lower-bounded sup-Semilattice for A being non empty
Subset of InclPoset(Ids L) holds ex_inf_of A,InclPoset(Ids L) & inf A = meet A
proof
let L be lower-bounded sup-Semilattice;
let A be non empty Subset of InclPoset(Ids L);
set P = InclPoset(Ids L);
reconsider A9= A as non empty Subset of Ids L by YELLOW_1:1;
meet A9 is Ideal of L by Th45;
then reconsider I = meet A as Element of P by Th41;
A1: for b being Element of P st b is_<=_than A holds I >= b
proof
let b be Element of P;
assume
A2: A is_>=_than b;
A3: for J being set st J in A holds b c= J
by A2,YELLOW_1:3;
b c= I
proof
let c be object;
assume
A4: c in b;
for J being set st J in A holds c in J
proof
let J be set;
assume J in A;
then b c= J by A3;
hence thesis by A4;
end;
hence thesis by SETFAM_1:def 1;
end;
hence thesis by YELLOW_1:3;
end;
I is_<=_than A
proof
let y be Element of P;
assume
A5: y in A;
I c= y
by A5,SETFAM_1:def 1;
hence I <= y by YELLOW_1:3;
end;
hence thesis by A1,YELLOW_0:31;
end;
theorem Th47:
for L being with_suprema Poset holds ex_inf_of {},InclPoset(Ids
L) & "/\"({}, InclPoset(Ids L)) = [#]L
proof
let L be with_suprema Poset;
set P = InclPoset(Ids L);
reconsider I = [#]L as Element of P by Th41;
A1: for b being Element of P st b is_<=_than {} holds I >= b
proof
let b be Element of P;
reconsider b9= b as Ideal of L by Th41;
assume {} is_>=_than b;
b9 c= [#]L;
hence thesis by YELLOW_1:3;
end;
I is_<=_than {};
hence thesis by A1,YELLOW_0:31;
end;
theorem Th48:
for L being lower-bounded sup-Semilattice holds InclPoset(Ids L) is complete
proof
let L be lower-bounded sup-Semilattice;
set P = InclPoset(Ids L);
for A being Subset of P holds ex_inf_of A,InclPoset(Ids L)
proof
let A be Subset of P;
per cases;
suppose
A = {};
hence thesis by Th47;
end;
suppose
A <> {};
hence thesis by Th46;
end;
end;
hence thesis by Th28;
end;
registration
let L be lower-bounded sup-Semilattice;
cluster InclPoset(Ids L) -> complete;
correctness by Th48;
end;
begin :: Special Maps
definition
let L be non empty Poset;
func SupMap L -> Function of InclPoset(Ids L), L means
:Def3:
for I being Ideal of L holds it.I = sup I;
existence
proof
deffunc F(set) = "\/"($1, L);
set P = InclPoset(Ids L);
A1: for I being set st I in the carrier of P
holds F(I) in the carrier of L;
ex f being Function of the carrier of P, the carrier of L st for I
being set st I in the carrier of P holds f.I = F(I)
from FUNCT_2:sch 11(A1);
then consider
f being Function of the carrier of P, the carrier of L such that
A2: for I being set st I in the carrier of P holds f.I = "\/"(I, L);
reconsider f as Function of P, L;
take f;
for I being Ideal of L holds f.I = sup I
proof
let I be Ideal of L;
I in the carrier of RelStr(#Ids L, RelIncl Ids L#);
then I in the carrier of P by YELLOW_1:def 1;
hence thesis by A2;
end;
hence thesis;
end;
uniqueness
proof
set P = InclPoset(Ids L);
let f, g be Function of InclPoset(Ids L), L;
assume that
A3: for I being Ideal of L holds f.I = sup I and
A4: for I being Ideal of L holds g.I = sup I;
A5: the carrier of P = the carrier of RelStr(#Ids L, RelIncl(Ids L)#) by
YELLOW_1:def 1
.= Ids L;
A6: now
let x be object;
assume x in the carrier of P;
then ex I being Ideal of L st x = I by A5;
then reconsider I = x as Ideal of L;
f.I = sup I by A3;
hence f.x = g.x by A4;
end;
dom f = the carrier of P & dom g = the carrier of P by FUNCT_2:def 1;
hence f = g by A6,FUNCT_1:2;
end;
end;
theorem Th49:
for L being non empty Poset holds dom SupMap L = Ids L & rng
SupMap L is Subset of L
proof
let L be non empty Poset;
set P = InclPoset(Ids L);
thus dom(SupMap L) = the carrier of P by FUNCT_2:def 1
.= the carrier of RelStr(#Ids L, RelIncl(Ids L)#) by YELLOW_1:def 1
.= Ids L;
thus thesis;
end;
theorem
for L being non empty Poset holds x in dom SupMap L iff x is Ideal of L
proof
let L be non empty Poset;
hereby
assume x in dom SupMap L;
then x in Ids L by Th49;
then ex I being Ideal of L st x = I;
hence x is Ideal of L;
end;
assume x is Ideal of L;
then x in the set of all X where X is Ideal of L;
hence thesis by Th49;
end;
theorem Th51:
for L being up-complete non empty Poset holds SupMap L is monotone
proof
let L be up-complete non empty Poset;
set P = InclPoset Ids L;
set f = SupMap L;
for x, y being Element of P st x <= y for a, b being Element of L st a =
f.x & b = f.y holds a <= b
proof
let x, y be Element of P such that
A1: x <= y;
reconsider I = x, J = y as Ideal of L by Th41;
A2: I c= J by A1,YELLOW_1:3;
A3: ex_sup_of I,L & ex_sup_of J,L by WAYBEL_0:75;
A4: f.x = sup I & f.y = sup J by Def3;
let a, b be Element of L;
assume a = f.x & b = f.y;
hence thesis by A3,A2,A4,YELLOW_0:34;
end;
hence thesis;
end;
registration
let L be up-complete non empty Poset;
cluster SupMap L -> monotone;
correctness by Th51;
end;
definition
let L be non empty Poset;
func IdsMap L -> Function of L, InclPoset(Ids L) means
:Def4:
for x being Element of L holds it.x = downarrow x;
existence
proof
deffunc F(Element of L) = downarrow $1;
A1: for x being Element of L holds F(x) is Element of InclPoset(Ids L) by Th41;
thus ex m being Function of L, InclPoset Ids L st for x being Element of L
holds m.x = F(x) from FUNCT_2:sch 9(A1);
end;
uniqueness
proof
let f1,f2 be Function of L,InclPoset(Ids L) such that
A2: for x being Element of L holds f1.x = downarrow x and
A3: for x being Element of L holds f2.x = downarrow x;
now
let x be Element of L;
thus f1.x = downarrow x by A2
.= f2.x by A3;
end;
hence thesis by FUNCT_2:63;
end;
end;
theorem Th52:
for L being non empty Poset holds IdsMap L is monotone
proof
let L be non empty Poset;
let x1,x2 be Element of L;
assume x1 <= x2;
then downarrow x1 c= downarrow x2 by WAYBEL_0:21;
then (IdsMap L).x1 c= downarrow x2 by Def4;
then
A1: (IdsMap L).x1 c= (IdsMap L).x2 by Def4;
let a, b be Element of InclPoset(Ids L);
assume a = (IdsMap L).x1 & b = (IdsMap L).x2;
hence a <= b by A1,YELLOW_1:3;
end;
registration
let L be non empty Poset;
cluster IdsMap L -> monotone;
correctness by Th52;
end;
begin :: A Family of Elements in a Lattice
definition
let L be non empty RelStr;
let F be Relation;
func \\/(F, L) -> Element of L equals
"\/"(rng F, L);
coherence;
func //\(F, L) -> Element of L equals
"/\"(rng F, L);
coherence;
end;
notation
let J be set, L be non empty RelStr;
let F be Function of J, the carrier of L;
synonym Sup F for \\/(F, L);
synonym Inf F for //\(F, L);
end;
reserve J for non empty set,
j for Element of J;
theorem
for F being Function of J, the carrier of L holds F.j <= Sup F & Inf F <= F.j
proof
let F be Function of J, the carrier of L;
F.j in rng F by FUNCT_2:4;
hence thesis by Th22;
end;
theorem
for F being Function of J, the carrier of L holds (for j holds F.j <=
a) implies Sup F <= a
proof
let F be Function of J, the carrier of L;
assume
A1: for j holds F.j <= a;
now
let c be Element of L;
assume c in rng F;
then consider j being object such that
A2: j in dom F and
A3: c = F.j by FUNCT_1:def 3;
reconsider j as Element of J by A2;
c = F.j by A3;
hence c <= a by A1;
end;
then rng F is_<=_than a;
hence thesis by YELLOW_0:32;
end;
theorem
for F being Function of J, the carrier of L holds (for j holds a <= F.
j) implies a <= Inf F
proof
let F be Function of J, the carrier of L;
assume
A1: for j holds a <= F.j;
now
let c be Element of L;
assume c in rng F;
then consider j being object such that
A2: j in dom F and
A3: c = F.j by FUNCT_1:def 3;
reconsider j as Element of J by A2;
c = F.j by A3;
hence a <= c by A1;
end;
then a is_<=_than rng F;
hence thesis by YELLOW_0:33;
end;